Scala stable multi-key sort with nulls last

import scala.util.Sorting

case class Row(name: String, age: Integer)

def compareRows(a: Row, b: Row): Int =
  val ageOrder = (Option(a.age), Option(b.age)) match
    case (None, None) => 0
    case (None, _) => 1
    case (_, None) => -1
    case (Some(x), Some(y)) => x.compareTo(y)
  if ageOrder != 0 then ageOrder else a.name.compareToIgnoreCase(b.name)

def sortRows(rows: Seq[Row]): Seq[Row] =
  val array = rows.toArray
  Sorting.stableSort(array)(using Ordering.fromLessThan((a, b) => compareRows(a, b) < 0))
  array.toSeq