JSON deserialization with line and byte error info

using System;
using System.Text.Json;

static T ParseJson<T>(string json, string label = "payload")
{
    try
    {
        return JsonSerializer.Deserialize<T>(json, new JsonSerializerOptions
        {
            PropertyNameCaseInsensitive = true
        }) ?? throw new JsonException("Deserialized to null.");
    }
    catch (JsonException ex)
    {
        throw new FormatException(
            $"Invalid JSON in {label} at line {ex.LineNumber + 1}, position {ex.BytePositionInLine + 1}: {ex.Message}", ex);
    }
}